25^2=5x^2-880

Solution for 25^2=5x^2-880 equation:

25^2=5x^2-880

We move all terms to the left:

25^2-(5x^2-880)=0

We add all the numbers together, and all the variables

-(5x^2-880)+625=0

We get rid of parentheses

-5x^2+880+625=0

We add all the numbers together, and all the variables

-5x^2+1505=0

a = -5; b = 0; c = +1505;
Δ = b2-4ac
Δ = 02-4·(-5)·1505
Δ = 30100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{30100}=\sqrt{100*301}=\sqrt{100}*\sqrt{301}=10\sqrt{301}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{301}}{2*-5}=\frac{0-10\sqrt{301}}{-10}
=-\frac{10\sqrt{301}}{-10}
=-\frac{\sqrt{301}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{301}}{2*-5}=\frac{0+10\sqrt{301}}{-10}
=\frac{10\sqrt{301}}{-10}
=\frac{\sqrt{301}}{-1}
$